Mathcad - C4-1

Дано: P = 12 кН, G = 48 кН, q = 4 кН/м,
α=120, M = 24 кНм
Q = 3 q = 12 кН
ΣFx=0: XA + P cos ( 30) = 0
XA = -P cos ( 30° ) = -12 cos ( 30 ° ) = -10.392 кН
ΣMa=0: YB 6 - Q 4.5 - G 3 - M - P  cos ( 30° ) 1 + P sin ( 30° )  3 = 0
Q 4.5 + G  3 + M + P cos ( 30° ) 1 - P sin ( 30° ) 3
6
12  4.5 + 48  3 + 24 + 12 cos ( 30 ° ) - 12 sin ( 30 ° )  3
YB =
= 35.732 кН
6
YB =
ΣMb=0: -YA 6 - M + G 3 + Q 1.5 - P  cos ( 30° ) 1 - P sin ( 30° )  3 = 0
-M + G 3 + Q 1.5 - P  cos ( 30° ) 1 - P sin ( 30° )  3
6
-24 + 48 3 + 12 1.5 - 12 cos ( 30 ° ) - 12 sin ( 30 ° ) 3
YA =
= 18.268 кН
6
YA =
YB = YB = 35.732 ; YA = YA = 18.268
ΣFy=0: YA + YB - G - Q + P sin ( 30° ) = 18.268 + 35.732 - 48 - 12 + 12 sin ( 30  ° ) = 0