I-вариант II-вариант (4 + 𝑎)2 = (5 + 𝑦)2 = (2𝑐 − 1)2 = (1 − 3𝑎)2 = (3𝑏 + 2𝑎)2 = (2𝑐 − 3𝑏)2 = (𝑥 4 − 3)2 = (𝑦 2 + 5)2 = (𝑎 + 1)3 = (3 + 𝑥)3 = (2 − 𝑎)3 = (𝑥 − 4)3 = I-вариант II-вариант (4 + 𝑎)2 = (5 + 𝑦)2 = (2𝑐 − 1)2 = (1 − 3𝑎)2 = (3𝑏 + 2𝑎)2 = (2𝑐 − 3𝑏)2 = (𝑥 4 − 3)2 = (𝑦 2 + 5)2 = (𝑎 + 1)3 = (3 + 𝑥)3 = (2 − 𝑎)3 = (𝑥 − 4)3 = I-вариант 2 II-вариант 2 (4 + 𝑎) = (5 + 𝑦) = (2𝑐 − 1)2 = (1 − 3𝑎)2 = (3𝑏 + 2𝑎)2 = (2𝑐 − 3𝑏)2 = (𝑥 4 − 3)2 = (𝑦 2 + 5)2 = (𝑎 + 1)3 = (3 + 𝑥)3 = (2 − 𝑎)3 = (𝑥 − 4)3 =