Безотражательное поглощение электромагнитного излучения

реклама
18
3, 2011
538.56:625.365
.
.
, . .
.
,
.
PACS: 41.20.-q
:
,
,
,
-
,
.
R
:
[1].
Z d cos
Z d cos
R
-
0
0
Z 0 cos
Z 0 cos
1
;
1
(1)
[2].
.
Z0 —
1—
cos
0
,
1.
,
=
–i ,
l
.
-
(
,
)
)
,
.
,
.
1
,
1
;
0
1 p;
1
1 p/
p sin 2
0
1;
[3].
(1)
Zd
-
:
Zd = Z1
Zd = Z1
19
. ., 2011
Z1 cos
Z cos
1
1
th( l cos
th( l cos
1)
1)
;
Z cos
Z1 cos
1
Z1 cos
Z cos
1
th( l cos
th( l cos
1)
1)
,
,
,
;
—
.
, AZ1143, .
, . .
, 29.
. (99412) 439-38-71.
(99412) 510-85-93.
E-mail: ITPCHT@itpcht.ab.az chem@science.az
Z cos
Z1 cos
(2)
.
.
.,
0
Z d cos
Z d cos
;
Z1, Z —
,
.
cos
0
—
—
(
Z 0 cos
Z 0 cos
R
,
;
1 p / ˆ;
cos
i2
2010 .
—
1
/
—
;
.
19
3, 2011
-
.
(4)
:
(5),
Zd = Z 0
cos
cos
1
:
;
0
(3)
Zd = Z 0
Z1
Z0 /
:
(2)
p
1
ˆ
p
cos
cos
1;
0
Y=
Z0 / ˆ ,
Z
i ˆ
p tg2 x
1
p tg2 x
i
.
1
Y=
1
P
n1P 1 1 P / n1 ;
(9)
1
P
n1P / n12 1 1 n12 P / n1 ;
(10)
tg4 x
p
1
;
1 p
2 PY
1 P2 1 Y 2
P
:
(4)
n
; Y
n1
P
ˆ
1
ˆ
p iˆ
p i
1
p tg2 x
ˆ
p tg2 x
1 p
,
1 p
1
(5)
1
p.
(4)
(5)
,
(12)
2y
y 1 y2
1 y2
2 yy
. (13)
,
,
1
,
-
Y
y;
2
2 yy
n 2n1 1 y
.
; Y
n12n
1 y2
P
l
x
1
1
(11)
,
-
-
,
,
,
1d
/ 4,
1
n2 1 y 2 ;
= 2n2y;
n
/ d;
n1
/ 1d ;
y tg / 2;
arctg / ;
d , 1d –
n12 ; y
1
n
,
[4].
(6)
,
,
,
,
1d
-
.
/ 2 [4].
,
.
-
:
-
p
;
1 p
,
,
1 p
;
,
p
,
1 p
1
1
(7)
,
(6)
1
-
:
2
n 1 y
2
n
d;
,
.
,
2
;
2n y ;
1
n12 ,
(8)
y
tg / 2;
1d
1d
/4
,
/ 4,
:
arctg
/ ;
,
/
n1
/ 1 p;
/
d,
,
1d ;
1d
/
1
,
p —
x
l
1d
2N 1
4
;
(14)
20
3, 2011
l
x
N
2
1d
.
-
(15)
,
0
.
N—
( 0 = 0)
=1
.
(14)
-
(15)
=
1
2
.
( )
0
0
(11), (14)
(11), (15):
0
1
2 PY
arctg
.
4
1 P2 1 Y 2
= 90
.
,
(16)
.
(4)
= 0,
P = n/n1 , Y = y,
:
=0
n, y
y, n1 n1.
(9)—(11)
1
n
y
tg4 x
n 1 n12 n ;
n12
p
-
2
p
1 p
.
(19)
60
70
(17)
1
2nn1 y
n12
n
,
2N 1 / 4 :
x
0
= 0, n
A = n1
= 0,
n2 1 y 2
(18)
,
1,0
,
[1] .
(14)
(15),
0, n, y
1
2
0,5
,
1d
-
/ 2.
l
,
(14)
0
0
2
(9)—(16)
-
0,20
-
0
=0
0,25
.
n,
,
. 1.
n
1
-
,
l0
,
1d
/ 4,
1d
0,
-
2
,
,
n
1
= 1,5
/4 (
)
0
1=
n
4-
.
.1
n
40
0,15
.
4
60
0,10
N
3
70
0,05
.
(15)
20 40
=0
1d
1,5
N = 1.
(1)
(2):
—
; N—
21
3, 2011
1
> 45
0
( )
,
0
1,0
=
2
( = –0,25)
=
( = 0) ,
>
.
(20),
-
70
0,5
n
58 60
50
65
45 40 30
55
0
1,5
58 65
55
0,05
60
58
60
0
2,5
0
(21)
0.
=0
2,0
50 40 30
45
65
arctg
-
,
n
=0
70
.
0
0,10
( )
-
0,15
,
0,20
0,25
=
1,
(20)
(21)
n
,
1d
/4 (
)
1d
.
/2
1,5
N = 1.
n
=
(2):
(1) 4-
>
—
; N—
1d
=0
-
.
0=
4
.
= 0).
=
( )
-
1d
/4 (
1d
/2 (
n
a
( n12
n18 1
p)
2
p
.
)
1 4ap
,
2a
= 0
–0,25 (
.
. 2).
(3)
1
-
)
0.
( = 0).
,
x (2 N 1) / 4 :
0
,
=0
-
,
0—45
= 1
( = –0,25)
= 1,
. 2)
( ),
0
,
.
0
(
( )
0
. 1).
(
—
.
0,25 (
( = – 0,25),
,
0.
,
=
(21).
-
/4
( = 0)
.
(20)
-
,
-
(15),
-
1=
,
.
.2
-
,
)
0
.
( )
0
. 2.
1d
=
,
,
,
(20)
,
,
1
.
,
-
22
3, 2011
,
-
( ),
(9) (10),
,
-
:
0
0
0,
.
0
;
2
1
0, l0
2
1
—
( )
,
;
;
[5].
—
—
-
(22)
,
0
0
l0
.
0<
0
(14)
l0
,
0>
(6)
-
,
(15)
.
4an 2 b2
a=(
0
+
n2
)/2; b = ( 0 –
-
(23)
a ,
)/2.
(9), (10)
l0
,
(23),
,
-
0,
,
1
,
0
l0,
0
.
2,
,
1
,
—
= 1,5 [5].
-
[ , ]
( )
(23)
-
0,
,
.
,
.
-
0
l0
,
0
,
0,
0
20
40
50
60
65
70
0
20
40
50
60
65
70
0
20
40
50
60
65
= 21,2;
=1,90;
= 3,01 10-12
0
4–
= 11,0;
= 2,52;
= 22 10-12
0
0=
5,74;
= 2,55;
= 7,0 10-12
.
-
0,
.
. 1
0
—
—
—
—
—
60
65
70
—
—
—
—
60
65
70
—
—
—
—
60
65
0,0584
0,0618
0,0773
0,0987
0,1545
0,2277
0,4681
1,1331
1,2133
1,5991
2,2104
5,2651
—
—
1,5384
1,9494
—
—
—
—
;
—
N0 = 1
0,0059
0,0065
0,0096
0,0138
0,0251
0,0402
0,0911
0,1378
0,1539
0,2308
0,3540
0,9823
—
—
0,2212
0,2965
—
—
—
—
l0,
; 0,
; N—
N0 = 2
0,0254
0,0277
0,0381
0,0521
0,0881
0,1354
0,2913
0,5155
0,5692
0,8208
1,2110
3,1318
—
—
0,7340
0,9639
—
—
—
—
, —
0,
N0 = 1
0,0059
0,0055
0,0036
0,0014
0,0049
0,0160
0,0399
0,1378
0,1298
0,0904
0,0463
0,1086
0,3413
0,9646
0,2211
0,1840
0,0952
0,0408
0,0901
0,4034
0,0585
0,0551
0,0394
0,0199
0,0180
0,0532
0,1158
1,1331
1,0568
0,7313
0,3667
0,3247
0,9978
2,5536
1,5384
1,2811
0,6826
0,2992
0,2613
1,0851
l0,
N0 = 2
0,0254
0,0244
0,0182
0,0091
0,0123
0,0384
0,0894
0,5155
0,4916
0,3602
0,1885
0,2412
0,7588
2,0566
0,7340
0,6227
0,3470
0,1568
0,1968
0,8574
,
.
23
3, 2011
,
(1)
(2)
R
,
0,56
(N = 1).
N=1(
= 3,2
0
. 3).
= 68,6
l0 = 0,61
,
-
,
(15).
0
,
-
,
-
0
4-
54,6
,
1 = 1,5.
—
,
(14)
= 3,2
-
l0 = 0,50
(
64,0
N = 1 ( . 4).
-
= 36,3
N =1),
0
= 1,22
R
1,0
0,8
0,6
0,4
2
0,2
1
0
10
20
30
40
50
60
. 3.
4-
70
80
0,
90
R
(1)
= 3,2
(2)
;
N= 1
0,56
20
0
0,61
,
.
(2),
.
;N—
1,0 R
0,8
0,6
0,4
2
0,2
1
0
10
20
30
40
50
60
70
80
90
0,
. 4.
N=1
R
0,50
= 3,2
;
20
(1) 1,22
;N—
—
0
24
3, 2011
-
,
.
-
1.
. .,
. .,
. .//
. 2000. 4. . 101.
2.
. .,
. .//
,
.
.- .
.
. 2004. . 24. 5. . 85.
3. Preisner J.// NTZ Arch. 1989. V. 11. No. 4. P. 175—182.
4.
. .
. — .:
, 1967.
5.
. .
. — .:
, 1999.
Reflectionless absorption of electromagnetic radiation at its falling
at an angle on the clarified swallowing wafer
R. M. Kasimov, S. R. Kasimova
Institute of Chemical Problems, 29 Javid av., Baku, AZ1143, Azerbaijan
E-mail: ITPCHT@itpcht.ab.az chem@science.az
Conditions of occurrence complete reflectionless absorption of an electromagnetic wave at its
falling at an angle on swallowing wafer of an infinite thickness with the layer put on it not swallowing dielectric are found. Their dependence on a thickness of a layer of a clarifying coating, an angle
of incidence of a wave and dielectric properties of a material of a wafer and a coating are researched.
PACS: 41.20.-q
Keywords: electromagnetic radiation, absorption, clarification, layer, wafer.
Bibliography — 5 references.
Received August 19, 2010
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